Question

Rahim deposited certain amount in a bank to earn interest at 10% per annum
He received 2662 from the bank after 3 years. Find the sum deposited.
(Please give the answer as soon as possible; it's important)​

Answer 1

Answer:

2662*10/100=266.2

10% =266.2

3 year = 266.2*3=798.6

2662-798=1864

Step-by-step explanation:

1864 rupee deposit

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Answer 2

$\sf \underline{for \:1 {}^{st} year}\\\bold{si} = \frac{x \times 5 \times 1}{100} \\ \sf{amount \: at \: the \: end \: of \: the \: first \: year = x + \frac{x}{20} = \frac{21x}{20} }$

$\sf \red {for \: 2 {n}^{d} year}$

$\sf {p = \frac{21x}{20} + x = \frac{41x}{20} } \\ \sf \: si \: for \: 2 ^{nd} = \frac{41x \times \cancel5 \times 1}{20 \times \cancel{100} } = \frac{41x}{400}$

$\sf \: amount \: at \: the \: end \: of \: 2 {}^{nd } year \: = \frac{41x}{400} + \frac{41x}{20} = \frac{861}{400} x$

$\sf \green{for \: 3 {}^{rd} year}$

$\sf \: p = \frac{861}{400} x + x = \frac{1261x}{400 }$

$\sf \: si \: for \: 3 {}^{rd} yr = \frac{1261x \times 5 \times 1}{100 \times 400} = \frac{1261}{8000} x$

$\sf \: amount \: at \: the \: end \: of \: 3 {}^{rd} year = \frac{1261x}{8000} + \frac{1261x}{400} \\ \sf = \frac{26481x}{8000}$