Rahim employed five men to develop a computer software, and they were able to complete it in 13 days. Had Rahim suspended two of them after the fourth day, then what would have been the total number of days in which the work would have been completed?
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5 men do the work in 13 days
So, 1 man will do the work in = 5 x 13 days = 65 days
So, work done by 1 man in 1 day = 1/65
Now,
After 4 days 2 men are suspended, so work done in 4 days will be = 4/13
Remaining work = 1 - 4/13 = 9/13
9/13 work has to be done by 3 men
3 men do 1 work in 65/3 days
So, 3 men will do 9/13 work in
9/13 x 65/3 = 15 days
Therefore total no. of days in which the work will get complete=
= 4 + 15
=21 days
So, 1 man will do the work in = 5 x 13 days = 65 days
So, work done by 1 man in 1 day = 1/65
Now,
After 4 days 2 men are suspended, so work done in 4 days will be = 4/13
Remaining work = 1 - 4/13 = 9/13
9/13 work has to be done by 3 men
3 men do 1 work in 65/3 days
So, 3 men will do 9/13 work in
9/13 x 65/3 = 15 days
Therefore total no. of days in which the work will get complete=
= 4 + 15
=21 days
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