Question

Rahim removes all the hearts from the cards. What is the probability o
i Getting an ace from the remaining pack.
ii Getting a diamonds.
jl Getting a card that is not a heart.
iv. Getting the Ace of hearts.​

Answer 1

Step-by-step explanation:

Since all hearts are removed, remaining cards 52-13= 39

I. P(ace) = 4-1

$\frac{3}{39}$

As one heart ace is removed

II. P(diamond)

$\frac{13}{39}$

III. P(non heart) = 39/39 = 1

IV. P( ace of hearts) = 0

Answer 2

Answer:

As all the heart is removed so the total number of cards left are = 52-13=39

1. Probability = 3/39 =1/13
2. Probability=13/39=1/3
3. Probability=39/39=1
4. Probability=0