rahim sets out to cross a forest.on the 1st day, he completes 1/10th of journey. on 2nd he covers 2/3rd of distance travelled 1st day. he continues in this manner alternating the days in which he travels 1/10th the distance still to be covered, with days on which he travels 2/3rd of total distance already covered. at the end of 7th day, he finds that twenty two nd half km more will see the end of his journey. how wide is the forest?
Answers
Answer:
let the total distance is 100%, so, on first day until 7 day is :10%+6.66%+16.66%+5.833%+31.666+2.0833=81.25% covered. remaining distance is 100% - 81.25% =18.75% 18.75% of X =22.5 km
X =22.5*100/18.75 =120 km
Answer:
120 km
Step-by-step explanation:
let , Assume total dist is 100% from 1st to unit 7 th day.
1 st day -10 %
2nd day -2/3 *10 =6.66%
3 rd day - 100-16.66%*1/10 = 8.334%
4 th day -10% +6.66+8.334 =24.994*2/3 = 16.66%
5 th day - 100- (10+6.66+8.334+16.66) =58.346*1/10 = 5.834%
6 th day - (10 +6.66+8.334+16.66+5.834)*2/3 =31.65%
7 th day - 100-(10+6.66+8.334+16.66+5.834+31.65)*1/10 =2.086%
Total Percentage from 1 to 7 is 81.224%
so , remaining is
100 - 81.224 = 18.75 % of X = 22.5 km
22.5*100/18.75 = x
X = 120 km.