Question

Rahm purchased a used car and sold it on 5% profit to Sarvesh Sarvesh spent Rs. 6500 on reparing i and
then he sold it on 10% profit to Mohan. Mohan sold i to Rita on 6% loss. Rita spent Rs. 1280 n repareg and
sold it to her relatives without any profit or loss in Rs.84000. What is the cost price (in rupees) of the Car
5
when Rahm bought it​

Answer 1

Step-by-step explanation:1)answer Rahm purchased a car - ₹ 5% the sarvesh spend - ₹ 6500 •°• the answer will be - ₹ 1300

i hope this answer will be help u

Answer 2

Rahm purchased the used car for Rs 70,000.

Given,

Rahm purchased a used car and sold it at a 5% profit to Sarvesh

Sarvesh spent Rs. 6500 on repairing and then he sold it on 10% profit to Mohan

Mohan sold it to Rita at a 6% loss

Rita spent Rs. 1280 repairing and sold it to her relatives without any profit or loss at Rs. 84000

To Find,

Price at which Rahm purchased the car

Solution,

Let the price at which Rahm purchased the car be 'x'

Cost at which Sarvesh purchased = x + 5% of x

Cost at which Sarvesh purchased = x + (5/100 * x)

Cost at which Sarvesh purchased = x + 0.05x

Cost at which Sarvesh purchased = 1.05x

Amount spent by Sarvesh on repairing  = 6500

The new cost of car = 1.05x + 6500

Cost at which Mohan purchased = (1.05x + 6500) + 10% of (1.05x + 6500)

Cost at which Mohan purchased = (1.05x + 6500) + 10/100 * (1.05x + 6500)

Cost at which Mohan purchased = (1.05x + 6500) + 0.1(1.05x + 6500)

Cost at which Mohan purchased = (1.05x + 6500) + 0.105x + 650

Cost at which Mohan purchased = 1.155x + 7150

Cost at which Rita purchased = (1.155x + 7150) - 6% of (1.155x + 7150)

Cost at which Rita purchased = (1.155x + 7150) - 6/100 * (1.155x + 7150)

Cost at which Rita purchased = (1.155x + 7150) - 0.06(1.155x + 7150)

Cost at which Rita purchased = (1.155x + 7150) - 0.0693x + 429

Cost at which Rita purchased = 1.0857x + 6721

Amount spent by Rita on repairing  = 1280

The new cost of car = 1.0857x + 6721 + 1280

The new cost of car = 1.0857x + 8001

Price at which Rita sold = 1.0857x + 8001

Also,

1.0857x + 8001 = 84000

1.0857x = 75999

x = $\frac{75999}{1.0857}$

x = Rs 70,000

Hence, Rahm purchased the used car for Rs 70,000.

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