Rahul a circular path of radius radius 28 may there is a road of uniform width 7m outside it find the area of the road use
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correct question: around a circular path having radius 28 m , there is a road outside it having width 7m . Find the area of the road.
Solution:
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let radius of the inner circle r = 28 m
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since , the width of road = 7 m
outer circle:
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Find the radius of outer circle:
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radius of outer circle R = radius of inner circular path + width of the road
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= 28m + 7m = 35 m
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Find the area of the road:
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area of the road
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= area of outer circle - area of inner circle
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= πR^2 - πr^2
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= π ( R^2 - r^2 )
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= π [ (35)^2 - ( 28 )^2 ]
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= π ( 1225 - 784 )
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= 441π = (441 × 22 ) / 7
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= 9702 ÷ 7 = 1386m^2
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Answer:
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area of the road = 1386 m^2
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Solution:
------------
let radius of the inner circle r = 28 m
.
since , the width of road = 7 m
outer circle:
-----------------
Find the radius of outer circle:
.
radius of outer circle R = radius of inner circular path + width of the road
.
= 28m + 7m = 35 m
.
Find the area of the road:
--------–-------------------------
.
area of the road
.
= area of outer circle - area of inner circle
.
= πR^2 - πr^2
.
= π ( R^2 - r^2 )
.
= π [ (35)^2 - ( 28 )^2 ]
.
= π ( 1225 - 784 )
.
= 441π = (441 × 22 ) / 7
.
= 9702 ÷ 7 = 1386m^2
.
Answer:
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area of the road = 1386 m^2
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