Question

Rahul borrow some money from Rajesh at 5% per annum for 2 years.if he paid rupees 51 2.50 as compound interest, what some did he borrowed?

Answer 1

let P = p
R= 5%pa
T=2years
CI = 512.50
$p( {(1 + \frac{r}{100} )^{t } - 1}) = 512.50$
$p(({1 + \frac{5}{100}}) ^{2} - 1) = 512.50$
$p(( { \frac{21}{20} })^{2} - 1) = 512.50$
$p(\frac{441}{400} - 1) = 512.50$
$p( \frac{41}{400} ) = \frac{51250}{100}$
$p = \frac{51250}{100} \times \frac{400}{41}$
$p = 5000$

Answer 2

Answer:

Take formula

P((1+r/100)-1) = c.i

Do yourself calculation

It's easy

Step-by-step explanation: