rahul borrowed some mony at 5% per annum for 2 years. if he paid 512.50 rs as compound interest, what sum did he borrow
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Answered by
3
let the principal be p
so the amount=p+512.50
=p+512.50=p(1+5/100)²
=p+512.50=p(1+1/20)²
=p+512.50=p(21/20)²
=p+512.50=441p/400
=400p+51250×4=441p
=41p=51250×4
=p=51250×4/41
=5000
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so the amount=p+512.50
=p+512.50=p(1+5/100)²
=p+512.50=p(1+1/20)²
=p+512.50=p(21/20)²
=p+512.50=441p/400
=400p+51250×4=441p
=41p=51250×4
=p=51250×4/41
=5000
hope you liked that follow me to continue getting answers
Answered by
1
let the principal = p
the amount=p+512.50
=p+512.50=p(1+5/100)²
=p+512.50=p(1+1/20)²
=p+512.50=p(21/20)²
=p+512.50=441p/400
=400p+51250×4=441p
=41p=51250×4
=p=51250×4/41
=5000
so therefore ur answer will be 5000
the amount=p+512.50
=p+512.50=p(1+5/100)²
=p+512.50=p(1+1/20)²
=p+512.50=p(21/20)²
=p+512.50=441p/400
=400p+51250×4=441p
=41p=51250×4
=p=51250×4/41
=5000
so therefore ur answer will be 5000
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