Question

Rahul bought a car Rs. 4 lakhs in 2018. The rate of
depreciation is 10% per year. Find the depreciation
value of the car in the year 2020?

Solution P=4,00,000 R= 10%, N=_years.
A=P(_______) (Formula)
On substituting the values of P, N, and R solving we get
A=4,00,000 X _______ square
= 4000 X (_______)
= Rs.________
Depreciation in price = Cost price - A
= Rs.________



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Answer 1

Answer

Answer1000 is not a perfect square.

Answer1000 is not a perfect square.31

Answer1000 is not a perfect square.31 2

Answer1000 is not a perfect square.31 2 <1000<32

Answer1000 is not a perfect square.31 2 <1000<32 2

Answer1000 is not a perfect square.31 2 <1000<32 2

Answer1000 is not a perfect square.31 2 <1000<32 2 Required no. of trees = 32

Answer1000 is not a perfect square.31 2 <1000<32 2 Required no. of trees = 32 2

Answer1000 is not a perfect square.31 2 <1000<32 2 Required no. of trees = 32 2 −1000

Answer1000 is not a perfect square.31 2 <1000<32 2 Required no. of trees = 32 2 −1000=1024−1000

Answer1000 is not a perfect square.31 2 <1000<32 2 Required no. of trees = 32 2 −1000=1024−1000=24.

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Answer 2

Answer:

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