Rahul bought a car Rs 4 lakhs in 2018. The rate of depreciation is 10°/• per year. find the depreciation value of the car in the year 2020?
solution p=4,00,000 R=10°/• N=___year
A=P(____)(Formula)
on substituting the value of P,N,and R solving we get
A=4,00,000×(____)®2
=4000×(____)
=Rs _____??
Depreciation in price=cost price-A
=Rs _______.
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Step-by-step explanation:
N=2 years
A=P(1+rt) where r =rate and the = time
A=4,00,000×(20/100× 2)=4,000×20×2=Rs 160000
I think my answer is correct and may help you
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