Question

Rahul bought a house for rupees 2,80,000 but due to some reason he sold the house for rupees 2,32,000 find his loss and loss percent.​

Answer 1

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Answer:

• Loss = Rs. 48,000
• Loss per cent = $17 \frac{1}{7}\%$

Given:

• Cost price of house = Rs. 2,80,000
• Selling price of house = Rs. 2,32,000

Need To Find:

• Loss = ?
• Loss per cent = ?

Explanation:

Case 1:

• Find the Loss = ?

Formula used here:

• Loss = CP - SP

Putting the values according to the given formula:

➠ Rs. 2,80,000 - Rs. 2,32,000

➠ Rs. 48,000

• Hence, the Loss = Rs. 48,000.

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Now, Case 2:

• Find the Loss per cent = ?

Formula used here:

• Loss % = Loss/CP × 100

Putting the values according to the given formula:

➠ 48000/280000 × 100

➠ $17 \frac{1}{7}\%$

• Hence, the loss per cent = $17 \frac{1}{7}\%$

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Additional Information:

Here,

• CP is used for Cost Price.
• SP is used for Selling Price.

• Loss = CP - SP
• Loss % = Loss/CP × 100

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Answer 2

ANSWER :

His loss is Rs 48,000 and percentage of loss is 17.14%( approx).

EXPLANATION :

GIVEN :-

• Cost price of the house= Rs 2,80,000.
• Selling Price of the house= Rs 2,32,000.

TO FIND :-

• Loss and loss percent.

SOLUTION :-

✪Cost price of the house= Rs 2,80,000.

✪Selling Price of the house = Rs 2,32,000.

★CASE 1 ★

We know ,

Loss = C.P - S.P

Loss = Rs( 2,80,000-2,32,000)

→ Loss = Rs 48,000

★CASE 2 ★

Loss percent = Loss/C.P ×100

=48,000/2,80,000 ×100

= 48/280 × 100

= 17.14 % ( approx)

Therefore, his loss is Rs 48,000 and percentage of loss is 17.14%( approx).

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MORE INFORMATION :-

• Profit = S.P - C.P
• Profit (%) = profit/S.P×100

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