Question

Rahul bought a second hand motorcycle for rupees 25400.He spend rupees 600 to repair it and sold to david at 6% loss how much did David pay for it ​

Answer 1

Given,

Rahul bought a second hand motorcycle for rupees $25400$. He spend rupees $600$ to repair it

So, Cost price $= 25400$

He spend $600$ rupees for repair

Total $=25400+600=26000$

David sold at $6$% loss

Loss $=26000\times\frac{6}{100}$

Loss $=1560$

Selling price $=26000-1560$

Selling price $=24440$

Therefore, $24440$ rupees David pay for motorcycle.

Answer 2

Answer:

$24440$

Step-by-step explanation:

Given data,

• Cost price of the motorcycle $=25400$

• Amount spent to repair the motorcycle $=600$

• Total amount spent $=25400+600=26000$

• Rahul sold the motorcycle to David at a loss of $6$%.

We know, loss% $=\frac{loss}{cost price}\times100$

$\Rightarrow 6=\frac{loss}{26000}\times100$

$\Rightarrow loss=6\times\frac{26000}{100}$

$\Rightarrow loss=1560$

Now, the selling price of the motorcycle at a loss of $6$%

$=26000-1560=24440$

Hence, David should pay $24440$.