Question

Rahul buys 3 types of balls. Type 1 costs ₹10 each, Type 2 costs ₹8 each, and

Type 3 costs ₹5 each. What is the least number balls of each type he should buy so

that he spends an equal amount on each type of ball?
please tell me It's a argent. ​

Answer 1

Answer:

4 ball

Step-by-step explanation:   LCM OF  10, 8 and 5 =40

        NOW,  40/10=4

                     40/8=5

                      40/5=8

               so,  4 is the least no,

Answer 2

Given: Rahul buys 3 types of balls. Type 1 costs ₹10 each, type 2 costs ₹8 each, and type 3 costs ₹5 each.

To find: The least number balls of each type he should buy so that he spends an equal amount on each type of ball.

Solution:

• In order to solve the given question, the L.C.M. of the prices of the three types of balls is found.

• The L.C.M. of 10, 8 and 5 is 40.

• Since the L.C.M. is 40, it means that he must spend atleast Rs. 40 in order to buy the balls.
• Now, 40 is divided by the cost of each ball seperately to find the number of balls to be bought.

        $\frac{40}{10} = 4$

        $\frac{40}{8} = 5$

        $\frac{40}{5} = 8$

Therefore, Rahul has to buy 4 of Rs. 10 balls, 5 of Rs. 8 balls and 8 of Rs. 5 balls so that he spends an equal amount on each type of ball.