Question

Rahul buys a phone for rupees 8000 and sells it at a loss of 10% he also buys of wrist watch for rupees 4500 and sells it at a profit of 10% calculate his total profit percent or loss percent

Answer 1

Answer:

Step-by-step explanation:

Given Rahul buys a phone for rupees 8000 and sells it at a loss of 10% he also buys of wrist watch for rupees 4500 and sells it at a profit of 10% calculate his total profit percent or loss percent

Cost price of phone = Rs 8000

So loss = 10%,  So 10/100 x 8000 = 800

Therefore Selling price = 8000 - 800 = Rs 7200

Now cost price of wrist watch = Rs 4500

Profit = 10%, so 10/100 x 4500 = Rs 450

So profit is Rs 450

Now selling price = 4500 + 450 = 4,950

So total selling price = 7200 + 4950 = 12,150

So total cost price = 8000 + 4500 = 12,500

So loss = cost price - selling price

  loss = 12,500 - 12,150

loss = Rs 350

So for 12,500 loss will be Rs 350

For 100 it will be 100 x 350 / 12500 = 2.8%

So loss percent will be 2.8%

Answer 2

Answer: Overall loss ℅ = 2.8 ℅

Step-by-step explanation:

Cost price( C.P) of the phone= Rs 8000

Loss ℅ = 10

Therefore, loss = 10℅ of 8000 = Rs 800

Hence, the selling price ( S.P) = Rs 8000 - 800 = Rs 7200

Cost price(c.p) of the watch = Rs 4500

Profit ℅ = 10

Therefore, profit = Rs. 450

Hence, the selling price(s.p) = Rs 4500+450 = Rs. 4950

Overall C.P = Rs 8000+4500 = Rs 12500

Overall S.P = Rs 7200 + 4950 = Rs. 12150

Since C.P > S.P so overall there is a loss

Overall loss = Rs 12500-12150 = Rs 350

Loss ℅ = (350/ 12500) × 100 = 2.8℅

Therefore, the net loss in the entire transaction is Rs 350 and loss ℅ is 2.8℅.