Rahul can do 2/7 of a certain work in 6 days while suresh can do 3/5 of the same work in 9 days. they started work together but after 7 days Rahul left the work. find in how many days Suresh can complete the remaining work?
Answers
To find the number of days Suresh takes to complete the remaining work, we take the whole work as x.
For Rahul,
2/7th of the work is done in = 6 days.
∴ The whole work is done in = 6 ×7/2=21 days.
∴ Work done in 1 day = 1/21 part of the work
For Suresh,
3/5 th of the work is done in = 9 days.
∴ The whole work is done in = 9 ×5/3=15 days.
∴ Work done in 1 day = 1/15 part of the work
Work done by Rahul and Suresh together in 1 day = 1/21+1/15=(5+7)/105=12/105 part of the work
∴ Work done by Rahul and Suresh together in 7 days = 12/105×7=12/15=4/5 part of the work
∴ Work left to be done = 1-4/5=(5-4)/5=1/5 part of the work.
1/5 part of the work is done by Suresh alone.
∴ 1/5 part of the work is done by Suresh in = 1/5÷1/15=1/5×15=3 days.
Hence, Suresh can complete the rest of the work in 3 days.
Answer:
3 days
Step-by-step explanation:
2/7 works is done = 6 days
the whole works is done =6*7/2=21 days
Suresh 3/5 work = 9
total work = 15
work together = 1/15 + 1/21= 12/105
together in 7 days = 7*12/105= 12/15
work done by 4/5
remaining work 1-4/5= 1/5
suresh done 1/5 works in 1/5 *15 = 3 days