Math, asked by rkohli5451, 1 year ago

Rahul can do 2 by 7 of a certain work in 6 days wle Suresh can do 3 by 5 of the same work in 9 days they started work together but after 7 days Rahul left the work find in how many days can complete the remaining work

Answers

Answered by sanjivkumar717p721mf
16
total work will be completed in 10 days. explanation is in picture.
Attachments:
Answered by RenatoMattice
11

Answer: The remaining work will be completed in 10 days.

Step-by-step explanation:

Since we have given that

Rahul can do 2 by 7 of a certain work in 6 days.

So, Number of days Rahul can do is given by

\dfrac{6}{\dfrac{2}{7}}\\\\=3\times 7\\\\=21

Suresh can do 3 by 5 of the same work in 9 days.

So, Number of days Suresh can do is given by

\dfrac{9}{\dfrac{3}{5}}\\\\=3\times 5\\\\=15\ days

But after 7 days Rahul left the work,

Work done by Rahul in 1 day = \dfrac{1}{21}

Work done by Rahul in 7 days = \dfrac{7}{21}=\dfrac{1}{3}

Remaining work will finished by Suresh.

Remaining work = \dfrac{2}{3}

Number of days to complete the remaining work is given by

\dfrac{2}{3}\times 15\\\\=2\times 5\\\\=10\ days

Hence, The remaining work will be completed in 10 days.

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