Question

Rahul can do a piece of work in 12 days and Manoj can do the same work in 7 days. They
work together for 2 days and then Manoj leaves. In how many days will Rohit alone finish
72
2
2
the remaining work?
T
11ictamin 4 hours and the tap 'B' can empty the full cistem in 6 hour Tf
AS​

Answer 1

Given :- Rahul can do a piece of work in 12 days and Manoj can do the same work in 7 days. They work together for 2 days and then Manoj leaves. In how many days will Rahul alone finish the remaining work ?

Solution :-

→ LCM of 12 & 7 = 84 unit = Let Total work.

So,

→ Efficiency of Rahul = (Total work) / (Total No. of Days.) = (84/12) = 7 units/day.

Similarly,

→ Efficiency of Manoj = (Total work) / (Total No. of Days.) = (84/7) = 12 units/day.

given that, they work together for 2 days.

So,

→ in 2 days they together finish the work = 2(7 + 12) = 38 units.

than,

→ Left work done to be done by rahul alone now = 84 - 38 = 46 units. { since Manoj leaves } .

Therefore,

→ Time taken by rahul to finish remaining work = (Left work) / (Efficiency of rahul) = (46/7) days. (Ans.)

Hence, Rahul alone take (46/7) days to finish the remaining work alone.

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