Question

Rahul can do a piece of work in 12 days and Manoj can do the same work in 16/2days.they work together for 6/2 days and then manoj leaves.in how many days will Rohit alone finish the remaining work?​

Answer 1

Answer:

Let Mohan and Manoj to do a piece of work be x.

Mohan takes 16 days less than Manoj to do a piece of work =

x−16

1

Mohan and Manoj working together =

x

1

+

x−16

1

=

15

1

x

2

−16x

2x−16

=

15

1

30x−240=x

2

−16x

x

2

−46x+240=0

Using

2a

−b±

b

2

−4ac

to find the value of x

⇒

2×1

46±

(−46)

2

−4×1×(240)

⇒

2

46±

1156

⇒

2

46±34

x=40, x=6

x cannot be negative.

Mohan alone complete the work = 40−16=24 hours.

and,

my name is also rahul