rahul deposited Rs 10,000. at the rate of 4%per annum in a bank on 11th january. on 18th august in same year he withdraw the entire amount lying in his account. find the amount bank gave to rahul.
Answers
Answered by
12
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GIVEN INFORMATIONS :-
(1) P = Rs. 10,000
(2) r = 4%
(3) t = 11th January to 18th August (219 days)
However, 219 days = 219/360 years
S. I. = Prt/100
=> S. I. = Rs. (10000×4×219)/(100×365)
=> S. I. = Rs. 240
Now, Amount (A) = S. I. + P
=> A = Rs. (240+10,000)
=> A = Rs. 10,240
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THUS THE AMOUNT BANK GAVE TO RAHUL IS Rs. 10240.
==================================
==================================
GIVEN INFORMATIONS :-
(1) P = Rs. 10,000
(2) r = 4%
(3) t = 11th January to 18th August (219 days)
However, 219 days = 219/360 years
S. I. = Prt/100
=> S. I. = Rs. (10000×4×219)/(100×365)
=> S. I. = Rs. 240
Now, Amount (A) = S. I. + P
=> A = Rs. (240+10,000)
=> A = Rs. 10,240
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THUS THE AMOUNT BANK GAVE TO RAHUL IS Rs. 10240.
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Answered by
3
GIVEN INFORMATIONS :-
(1) P = Rs. 10,000
(2) r = 4%
(3) t = 11th January to 18th August (219 days)
However, 219 days = 219/360 years
S. I. = Prt/100
=> S. I. = Rs. (10000×4×219)/(100×365)
=> S. I. = Rs. 240
Now, Amount (A) = S. I. + P
=> A = Rs. (240+10,000)
=> A = Rs. 10,240
(1) P = Rs. 10,000
(2) r = 4%
(3) t = 11th January to 18th August (219 days)
However, 219 days = 219/360 years
S. I. = Prt/100
=> S. I. = Rs. (10000×4×219)/(100×365)
=> S. I. = Rs. 240
Now, Amount (A) = S. I. + P
=> A = Rs. (240+10,000)
=> A = Rs. 10,240
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