Rahul diposite sum of Rs 10,000 at the rate of 4% per annum in a bank on 11 january. on 18th august in the same year he withdrew the entire amount lying in his account. find the amount bank gave to rahul.
Answers
Answered by
12
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GIVEN INFORMATIONS :-
(1) P = Rs. 10,000
(2) r = 4%
(3) t = 11th January to 18th August (219 days)
However, 219 days = 219/360 years
S. I. = Prt/100
=> S. I. = Rs. (10000×4×219)/(100×365)
=> S. I. = Rs. 240
Now, Amount (A) = S. I. + P
=> A = Rs. (240+10,000)
=> A = Rs. 10,240
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THUS THE AMOUNT BANK GAVE TO RAHUL IS Rs. 10240.
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==================================
GIVEN INFORMATIONS :-
(1) P = Rs. 10,000
(2) r = 4%
(3) t = 11th January to 18th August (219 days)
However, 219 days = 219/360 years
S. I. = Prt/100
=> S. I. = Rs. (10000×4×219)/(100×365)
=> S. I. = Rs. 240
Now, Amount (A) = S. I. + P
=> A = Rs. (240+10,000)
=> A = Rs. 10,240
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THUS THE AMOUNT BANK GAVE TO RAHUL IS Rs. 10240.
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Answered by
3
GIVEN INFORMATIONS :-
(1) P = Rs. 10,000
(2) r = 4%
(3) t = 11th January to 18th August (219 days)
However, 219 days = 219/360 years
S. I. = Prt/100
=> S. I. = Rs. (10000×4×219)/(100×365)
=> S. I. = Rs. 240
Now, Amount (A) = S. I. + P
=> A = Rs. (240+10,000)
=> A = Rs. 10,240 [REQUIRED ANSWER]
(1) P = Rs. 10,000
(2) r = 4%
(3) t = 11th January to 18th August (219 days)
However, 219 days = 219/360 years
S. I. = Prt/100
=> S. I. = Rs. (10000×4×219)/(100×365)
=> S. I. = Rs. 240
Now, Amount (A) = S. I. + P
=> A = Rs. (240+10,000)
=> A = Rs. 10,240 [REQUIRED ANSWER]
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