Rahul got 12,00,000 in inheritance. Some part of this money he invested at 10% and balance he
invested at 15% simple interest. His annual income by these investments is 1,55,000. How much
money did he invest for each rate of interest?
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Answer:
Let X be money which is given at 10% intrest
Hence 12,00,000-x will be the money which is invested at 15% interest
Interest gained by money x for 1 year is=(x*1*10)/100
Interest gained by money 1200000-x for 1 year is=[(1200000-x)*1*15]/100
toatal amount gained is 155000
hence [(x*1*10)/100] + [(1200000-x)*1*15]/100=155000
on solving this equation we get value of x = 500000
hence x i.e, 500000is invested at 10% and remaining 1200000-x i.e, 700000 is invested at rate of 15%
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