rahul got ₹ 1200000 inheritance. some part of this money he invested at 10% and balance he invested at 15% simple interest. his annual income by these investment is ₹ 155000. how much money did he invest for each rate of interest ?
a genius can solve this
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Hello my dear friend I think genius is not necessary to solve this problem.Here is ur answer
- Let X be money which is given at 10% intrest
- Hence 12,00,000-x will be the money which is invested at 15% interest
- Interest gained by money x for 1 year is=(x*1*10)/100
- Interest gained by money 1200000-x for 1 year is=[(1200000-x)*1*15]/100
- toatal amount gained is 155000
- hence [(x*1*10)/100] + [(1200000-x)*1*15]/100=155000
- on solving this equation we get value of x = 500000
- hence x i.e, 500000is invested at 10% and remaining 1200000-x i.e, 700000 is invested at rate of 15%
sauravben:
please solve this 1) A motorboat when moving downstream covers the distance between two cities in 4 hours, while it covers the same distance upstream in 5 hours. If the speed of the river is 2km/h, find the speed of the motorboat in still water.
Let x be the speed of the boat and given speed of the boat as 2km/hr.Let D be the distance between 2 cities.While boat is moving downstream then speed becomes x+2
Hence we know that D=ST.From this we can write D=(x+2)4-------->1 when boat is moving downstream
When boat is moving upstream its speed will be x-2 hence from this we can write D=(x-2)5------>2.(distance in upstream=dowmstream)
On solving these two equations we get x=18 which is speed of boat and D=80 which is distance between 2 cities
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