Rahul has applied a force of 100 N on an object, at an angle of 60 degree to the horizontal. The object gets displaced in the horizontal direction and 800 J work is done. What is the displacement of the
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A = 60°
F = 100N
W= 800j , s=?
W=F×s×CosA
400=100×s×1/2
400/100=s×1/2
4×2=s
s = 8
the object will be displacement is 8m
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