Rahul invested 15000 for 2 years at CI.After one year it amounts to 16200 .find rate of interest.
Answers
Answered by
0
Answer:
4%(approx)
Step-by-step explanation:
Principal = RS 15000
Amount = RS 16200
Time = 2 years
Let Rate = R%
By using formula
A = P(1 + R/100) ^n
16200 = 15000 (1 + R/100)^2
(1+R/100)^2= 16200/15000
(1+R/1000)^2=27/25
On cancelling the square
1+R/100 = 3sqrt3/ 5
R/100 = 1.732*3/5 - 1
R/100 = 5.196/5 - 1
R/100 =0.196/5
R=0.196*100/5
R=0.196* 20
R= 3.92
R= 4% (approx)
Answered by
3
Answer:
4%(approx)
Solution:
Principal = RS 15000
Amount = RS 16200
Time = 2 years
Let Rate = R%
By using formula
A = P(1 + R/100) ^n
16200 = 15000 (1 + R/100)^2
(1+R/100)^2= 16200/15000
(1+R/1000)^2=27/25
On cancelling the square
1+R/100 = 3sqrt3/ 5
R/100 = 1.732*3/5 - 1
R/100 = 5.196/5 - 1
R/100 =0.196/5
R=0.196*100/5
R=0.196* 20
R= 3.92
R= 4% (approx)
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