Rahul invested rupee 7,000in2year at the rate of 12percent per annum compounded annually what is the compound interest that rahul gets after 2years
Answers
Answered by
0
Answer:
p=7000
t=2yrs
r=12%
compound interest =amount-principle
amount=p[1+r/100]power n
=7000[1+12/100] power 2
= 7000×112/100×112/100
=21952/-
14952
compound interest=21952-7000
Answered by
0
Answer:
1780.80
Step-by-step explanation:
at first,
A=P(1+r/100)^n
=7000(1+12/100)^2
=7000(112/100)^2
=7000*112/100*112/100
=7*112*112/10
=87808/10
=8780.8
therefore,
A=8780.8
we know,
compound interest =Amount -principle
=8780.8-7000
=1780.80
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