Question

Rahul invested rupee 7,000in2year at the rate of 12percent per annum compounded annually what is the compound interest that rahul gets after 2years​

Answer 1

Answer:

p=7000

t=2yrs

r=12%

compound interest =amount-principle

amount=p[1+r/100]power n

=7000[1+12/100] power 2

= 7000×112/100×112/100

=21952/-

14952

compound interest=21952-7000

Answer 2

Answer:

1780.80

Step-by-step explanation:

at first,

A=P(1+r/100)^n

=7000(1+12/100)^2

=7000(112/100)^2

=7000*112/100*112/100

=7*112*112/10

=87808/10

=8780.8

therefore,

A=8780.8

we know,

compound interest =Amount -principle

=8780.8-7000

=1780.80