Math, asked by akshat07srivastava, 1 month ago

Rahul invests 5600 at 14%per annum compound interest for 2 years. calculate. a. the interest for the second year correct to the nearest​. b. interest for 1 years c. amount after 2 years. please tell​

Answers

Answered by hetvimange111
1

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Answered by sinharanveer321
1

Step-by-step explanation:

1st year

P=Rs=5600,N=1 Year and R =14%

We have,

S.I= PNR by 100=5,600×1×14 by 100=Rs 784 ans

and amount at the end of first year P+

S.I=Rs.5600+Rs 784 = Rs.6,384

Now the second year

For 2nd year

P=6384,R=14%,N=1Year=

S.I.=

PNR by 100 =6,384×14×1 by 100 =Rs - 893 ans

To the nearest rupees ,it is rs.894

(nearly)

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