Rahul invests 5600 at 14%per annum compound interest for 2 years. calculate. a. the interest for the second year correct to the nearest. b. interest for 1 years c. amount after 2 years. please tell
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Step-by-step explanation:
1st year
P=Rs=5600,N=1 Year and R =14%
We have,
S.I= PNR by 100=5,600×1×14 by 100=Rs 784 ans
and amount at the end of first year P+
S.I=Rs.5600+Rs 784 = Rs.6,384
Now the second year
For 2nd year
P=6384,R=14%,N=1Year=
S.I.=
PNR by 100 =6,384×14×1 by 100 =Rs - 893 ans
To the nearest rupees ,it is rs.894
(nearly)
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