rahul is 4 times as old as his son after 16 years he will be twice old as his son his sons present age
Answers
Answer:
Let son's age is x years
father is 4 times older than his son hence father age will be 4x
In 20 years he will be twice as old as his son. After 20 years their ages will be
Son age = x + 20
Father's age = 4x + 20
4x + 20 = 2 ( x + 20 )
Solving the equation
4x + 20 = 2x + 40
4x - 2x = 40 - 20
2x = 20
x = 10
The son's present age is 10 years
Father's age is 4x= 4 × 10 = 40 years.
Answer son's present age 10 years and father's present age is 40 years
Let us check the correctness of answer by putting their respective ages in the equation.
4x + 20 = 2x + 40
4 × 10 + 20 = 2×10 + 40
40 + 20 = 20 + 40
60 = 60
Step-by-step explanation:
Answer:
let the Rahul's son age be x years
Rahul age = 4 × x
= 4x
after 16 years,
Rahul age 4x+16
Rahul's son age x+16
4x+16 = 2(x+16) ( Rahul's age is twice his son age)
4x+16=2x+32
4x-2x=32-16
2x=16
x=8
Rahul's son is 8 years old
Rahul age = 4×8=32 years