Question

Rahul is twice old as rohit.Four years hence the product of their ages will be 160.Find their present ages.

Answer 1

Answer:

Step-by-step explanation:

Let rohit be x yrs old

So, Rahul is 2x yrs old

4 yrs hence

Rahul=2x+4

Rohit = x+4

(2x+4) (x+4) =160

2x^2+12x+16=160

Answer 2

Answer:

age of  Rahul=2x =12

 age of Rohit = x =6

Step-by-step explanation:

Let rohit be x yrs old

So, Rahul is 2x yrs old

4 yrs hence

age of  Rahul=2x+4

 age of Rohit = x+4

product (2x+4) (x+4) =160

   2x^2+12x+16=160

x^2 +6x +8 = 80

x^2 +6x -72 =0

[x+12] [x-6] =0

x= -12 is not an age   x= 6

age of  Rahul=2x =12

 age of Rohit = x =6