Question

Rahul owns a rectangular field of length 400m and breadth 200m.his friend ramu owns a squre field of length 300m.find the cost of fencing the two fields at₹150 per meter .if one tree can be planted in an area of 10sq m. who can plant more tress in his field?how many more tress can he plant?

Answer 1

area of rahul's field = 400*200 = 80000m²
area of ramu's field = 300*300 = 90000m²
cost of fencing the fields = 150*(80000+90000) = ₹25500000

no. of trees rahul can plant = 80000/10 = 8000
nom of trees ramu can plant = 90000/10 = 9000
hence, ramu can plant 1000 more trees. (9000-8000=1000)

Answer 2

For Rahul's field,
Given,
l=400m
b=200m
Therefore, perimeter=2(l+b)
=2(400+200)m
=1200m
Therefore, Cost for fencing the field=Rs150*1200
=Rs 180000
Again,
Area of the field=l*b
=400*200 m²
=80000 m²
Therefore,the no. of trees Rahul can plant=80000m²/10m²
=8000
For Ramu's Field,
Given,
side=300m
Therefore, Perimeter=4*s
=4*300m
=1200m
Therefore, cost of fencing the field=Rs150*1200
=Rs 180000
Again,
Area of the field=S*S
=300*300 m²
=90000m²
Therefore, no. of trees ramu can plant=90000m²/10m²
=9000
Therefore, Ramu can plant more trees than Rahul by 9000-8000=1000 trees