Math, asked by sunchusiddartha456, 3 months ago

rahul owns a rectangular field of length 400m and breadth 200m his friend ramu owns a square field of length 300m find the cost of fencing of the two fields at rs150 pet meter if one tree can be placed in an area of 10sqm who can plant more trees in his field how many trees can be planted​

Answers

Answered by anjulsummit
0

Answer:

happy independent day in advance

Answered by ark212002
0

Answer:

Rs. 3,60,000

Ramu

Step-by-step explanation:

Total \: perimeter = 2(400+200)+4 \times 300 = 2 \times 600+1,200 = 1,200+1,200 = 2,400 \\ cost = 150 \times perimeter = 150 \times 2400 = Rs. 3,60,000 \\ Area \: of \: Rahul's \: field = 400 \times 200 = 80,000 \\no. \: of \: trees \: planed \: by \: rahul =  \frac{80,000}{10} = 8,000 \\ Area \: of \: Ramu's \: field =  {300}^{2}  = 90,000 \\ no. \: of \: trees \: planed \: by \: ramu =  \frac{90,000}{10}  = 9,000

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