Math, asked by misrapiyu, 1 month ago

rahul's age is three times his sons age, 10 yrs ago rahul was five times hus son's age.Find present age with proper steps​

Answers

Answered by 12495pratyush
1

Answer:

Step-by-step explanation:

A man's age is three times his son's age.Ten years ago he was five times his son's age.

By forming two equations and solving them simultaneously,find both of their ages.

:

Let m = man's present age

let s = son's present age

:

Write an equation for each statement:

:

"A man's age is three times his son's age"

m = 3s

m - 3s = 0

:

"Ten years ago he was five times his son's age."

m - 10 = 5(s-10)

m - 10 = 5s - 50

m - 5s = -50 + 10

 

m - 5s = -40

multiply by -1 to change the signs, add to the first equation

-m + 5s = 40

+m - 3s = 0

------------adding eliminates m, find s

2s = 40

s = 40/2

s = 20 yr is the son's age

then

m = 3(20)

m = 60 is the man's age

Answered by kumararyan56
1

Answer:

Present age of Rahul's son ≈ 20

Present age of Rahul is ≈ 60

Step-by-step explanation:

Let the son's age =x

Than Rahul age = 3x

10 yrs age of Rahul = (3x-10)

10 yrs age of Rahul son = (x-10)

Given that ,

Rahul is five times of his son age ...

So,

→3x-10≈ 5(x-10)

→3x-10≈5x-50

→3x-5x≈ -50+10

→ -2x ≈ -40

→ x≈ -40/-2

→x=20

Present age of Rahul's son ≈ 20

Present age of Rahul is ≈ 60

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