Rahul sold a watch to Sohan at a gain of 10% and Sohan sold it to Mohan at a loss of 10% . If Mohan paid rs 990 for it , find the price paid by Rahul
Answers
X=10×10×10
X=1000
Rs1000 paid by rahul
Given:
Rahul sold a watch to Sohan at a gain of 10%, Sohan sold it to Mohan at a loss of 10%. Mohan paid 990 rupees to Sohan.
To Find:
The price paid by Rahul is?
Solution:
1. Let the initial cost of the watch be x. ( Initial cost implies the cost at which Rahul has bought the watch).
2. Rahul has sold the watch to Sohan at a gain of 10%,
=> Price at which Rahul has sold it to Sohan = x + (10/100) * x,
=> Price at which Rahul has sold it to Sohan = 11x/10.
3. Sohan sold the watch to Mohan at a loss of 10%,
=> Price at which Sohan has sold it to Mohan = 11x/10 - (10/100) 11x/10,
=> Price at which Sohan has sold it to Mohan = 99x/100.
4. Mohan has paid 990 rupees to Mohan,
=> 99x/100 = 990,
=> x = 1000.
5. x = 1000 implies the original price of the watch. ( Price at which Rahul has bought the watch).
Therefore, Rahul has bought the watch for 1000 INR.