Math, asked by aashika3, 1 year ago

Rahul sold a watch to sohan at a gain of 10 percent and sohan sold it to mohan at a loss of 10 percent .If mohan paid rs 990 for it ,find the price paid by rahul.

Answers

Answered by panda013
2
10% of 990 = 10/100*990 =99
99 + 990=1980
therefore, rahul purchased it in rupees 1980 - 99 = rupees 990
hope it helps thnq ☺
Answered by tnwramit1
4
Let

Rahul bought the watch =100

So now he sold it to sohan at 10% gain

So selling price=cpx(100+gain%)/100

=100x(100+10)/100

=100x110/100

=110

Now sohan sold it to mohan at 10% loss

(Now cp=110)
Then sp=cpx(100-loss%)/100

=110x(100-10)/100

=110x90/100

=11x9

=99

But according to question mohan paid =₹990

One unit assumed =990/99 =10

Then rahul paid =100x10=₹1000

This is ur ans hope it will help you in case of any doubt comment below
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