Question

Rahul walks 12m North from his house and turns West to walk 35 m to reach his friend’s house .While returning he walks diagonally from his friends house to reach back to his house.What distance did he walk while returning?

Answer 1

by using Pythagorean triplet

Answer 2

Given:

Distance walked in North direction=12m

Distance walked in West direction=35m

To find:

The diagonal distance walked by Rahul while returning

Solution:

The diagonal distance walked by Rahul while returning is 37m.

We can find the distance by following the given steps-

We know that the distance walked by Rahul forms a triangular shape.

From his house, Rahul walked towards the North and then turned towards the West.

The diagonal distance from his friend's house to his own house forms the hypotenuse.

Let this distance be D.

So, in this triangle, the length of the perpendicular is 12m and the length of the base is 35m.

We will use the Pythagoras theorem to obtain the distance.

Using the Pythagoras theorem, we get

$Base^{2} +Perpendicular^{2} =Hypotenuse^{2}$

$35^{2}+12^{2} =D^{2}$

1225+144=$D^{2}$

1369=  $D^{2}$

37=D

So, the distance walked is 37m.

Therefore, the diagonal distance walked by Rahul while returning is 37m.