Question

Rahul walks 12m north from his house and turns west to walk 35m to reach his friend’s house. While returning, he walks diagonally from his friend’s house to reach back to his house. What distance did he walk while returning?

Answer 1

Answer:

37 m = distance while returning

Step-by-step explanation:

He covered 12 m north.

He turns west from north, which is at 90° for north. Then covers a distance of 35 m.

By Pythagoras theorem:

= > length of diagonal^2

= > diagonal² = 12^2 + 35^2 m^2

= > diagonal² = 369 m^2 = ( 37 m )^2

= > diagonal = 37 m

Hence,

Total distance covered while returning = 37 m

Answer 2

$\bigstar$ Question :

Rahul walks 12 m north from his house and turns west to walk 35 m to reach his friend’s house. While returning, he walks diagonally from his friend’s house to reach back to his house. What distance did he walk while returning?

$\bigstar$ Answer :

$\bigstar$ Given :

• Rahul walks 12 m north from his house

• He turns west to walk 35 m to reach his friends house

$\bigstar$ To Find :

• He walks diagonally from his friend’s house to reach back to his house. What distance did he walk while returning

$\bigstar$ Explanation :

It is clearly appears as right angled triangle . We need to find the hypotenuse of right angled triangle.

where , other two sides are 12 m and 35 m respectively.

Here hypotenuse is nothing but the displacement.

So , A/c to Pythagoras Theorem ,

(hyp.)² = (opp. side)² + (adj. side)²

(hyp.)² = 12² + 35²

$\implies \bf{\red{\bold{hyp. = 37\;m}}}$

So , while returns he walks 37 m