Question

Rahul walks 4 km Straight, turns left and walks 3 km straight, then again turns left and travels 8 km straight again. how far is Rahul from his starting point?​

Answer 1

$\large{\underline{\underline{\mathfrak{\green{\sf{QUESTION:-}}}}}}$.

• Rahul walks 4 km Straight, turns left and walks 3 km straight, then again turns left and travels 8 km straight again. how far is Rahul from his starting point...?

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$\large{\underline{\underline{\mathfrak{\green{\sf{SOLUTION:-}}}}}}$.

We take here ,

$\bold{\triangleADE\:in}$

By Pythagoras theorem ,

$\bold{\boxed{\boxed{\:AE^2\:=\:(AD^2+DE^2)}}}$

Where, AD = 3, DE = 4

$\implies\:AE^2\:=\:(3^2+4^2)$

$\implies\:AE^2\:=\:(9+16)$

$\implies\:AE^2\:=\:(25)$

$\implies\:AE\:=\:±\sqrt{25}$

$\implies\:AE\:=\:±5$

But we know , Distance always be positive

So,

$\bold{\boxed{\boxed{\:AE\:=\:5}}}$

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$\large{\underline{\underline{\mathfrak{\green{\sf{ANSWER:-}}}}}}$.

• 5KM for his is rahul from starting point .

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Answer 2

QUESTION:-

(RAHUL WALKS 4KM STRAIGHT ,TURNS LEFT AND WALK 3KM STRAIGHT,THEN AGAIN TURNS LEFT AND TRAVEL 8KM STRAIGHT AGAIN.HOW FAR IS RAHUL FROM HIS STARTING POINT.??)

$\huge \mathfrak \orange{answer}$

BY PYTHAGORAS THEORAM..

(AE)²=(AD²+DE²)

AD=3 ((AND)) DE=4

AE²=(3²+4²)

AE² =(9+16)

AE²=25

AE=

$\sqrt{25}$

AE=5 KM..

RAHUL STARTING POINT AT THE DISTANCE IS 5KM..♥️

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