Question

Rahul was not attentive in his class, so to give him punishment his teacher asked him to find numbers
of two digit number that leaves the remainder 1 when divided by 5.​

Answer 1

Answer:

Step-by-step explanation:

It is a case of AP where a = 6, d = 5, nth term is 96

96 = 6 + (n - 1) 5

96 = 6 + 5n - 5

5n = 96 - 1 = 95

n = 95/5 = 19

So there are 19 two digit numbers

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Answer 2

In total there are eighteen two-digit numbers that leave the remainder 1 when divided by 5.

Step-by-step explanation:

We need to find the two-digit numbers that will leave the remainder 1 when divided by 5.

If we examine the two-digit numbers starting from 10, we find that 10 is exactly divisible by 5. The next number is 11. On dividing 11 by 5, we find that it will leave 1 as a remainder.

Thus, 11 is the first two-digit number, which when divided by 5 will leave the remainder 1.

Now, the next number in the series would be 5+11 = 16.

Similarly, other numbers would be: 16 + 5 = 21,

21 + 5 = 26,

26 + 5 = 31,

31 + 5 = 36,

36 + 5 = 41,

41 + 5 = 46,

46  + 5 = 51,

51 + 5 = 56,

56 + 5 = 61,

61 + 5 = 66,

66 + 5 = 71,

71 + 5 = 76,

76 + 5 = 81,

81 + 5 = 86,

86 + 5 = 91, and

91 + 5 = 96

Hence, there are 18 such numbers.