Question

Rain appears to fall vertically to a man when he is stationary but when he starts moving at speed of 10km/h the rain drops appears to strike him at an angle of 45degree from the vertical then determine the actual velocity of the rain drops​

Answer 1

Explanation:

Initial velocity of the man, me = 4 m/s Final velocity of the man, m'e = 8 m/s

m'm = m'e - me = 8 - 4 = 4 m/s

tan 45 = rm/m'm

rm = (m'm) tan 45 = 1 =

re = v(rm)^2 + (me)^2 = 4 v2 m/s =

e = tan^-1 (me / rm) = tan^-1 (1)

e = 45° degree

Hence the speed of the raindrop is 4 v2 m/s and the angle is 45°.

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