rain is falling in vertically downward direction with speed 10√3 km/h. if wind is blowing in eastward direction with speed 10km/h, then the velocity of rain observed by a person standing on the ground is
a. 20km/h
b. 10km/h
c. 10√3km/h
d. 10(√3-1)km/h
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Given:
Speed of the rain falling vertically = 10√3 km/hr
Speed of wind blowing in eastward direction = 10 km/hr
To find:
The velocity of rain observed by a person standing on the ground.
Solution:
The resultant velocity of wind will be observed by the person standing on the ground.
Speed of wind = -10√3 j km/hr
Speed of wind = 10 i km/hr
Magnitude of resultant velocity |v| = √(-10√3)²+(10)² = 20 km/hr
Angle made by resultant velocity from horizontal (+ve x axis):
tanα= -10√3/10 = -√3 = -60°
Velocity of rain = 20 cos(-60)°i - 20 sin (60)° j
= 10 i - 10√3j km/hr
Therefore the velocity of rain as observed by the person is 10i - 10√3j km/hr.
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