Rain is falling vertically with a speed of 25m/s after some time wind starts blowing with speed of 10m/s in north to south direction in what direction man should stand hold his umbrella in order to protect himself from rain with what speed rain strike his umbrella
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the magnitude of the result velocity of the rain drops =
√(20²+8²) = 21.54 m / sec
the direction of the resultant velocity vector with the vertical
= tan ⁻¹ (8/20) =38.05 deg.
The umbrella should be pointed in the direction opposite to the resultant velocity of the rain drops. So it should be in the direction 38.05deg. inclination to the vertical opposite to the direction of wind., towards East.
√(20²+8²) = 21.54 m / sec
the direction of the resultant velocity vector with the vertical
= tan ⁻¹ (8/20) =38.05 deg.
The umbrella should be pointed in the direction opposite to the resultant velocity of the rain drops. So it should be in the direction 38.05deg. inclination to the vertical opposite to the direction of wind., towards East.
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