Question

rain was falling in a non windyday vertically downwards at the rate of 12m/s suddenly wind stsrts blowing at the rate of 4 m.sdue north with what speed the train dropd hit a man traveling due at eadt at 3m/s.

Answer 1

hope this helps you.

Answer 2

The train will hit the man at 13m/s.

Step by step Explanation:

Given: Rain falling vertically downward$= 12m/s$

           wind blowing in the north direction$=4m/s$

           man's speed in the east direction$=3m/s$

To find: At what speed the train will hit the man?

How to find the resultant vector?

If two vectors are in a different direction then the resultant vector

will be $=\sqrt{(a^{2}+b^{2}) }$

so the resultant rain speed$=\sqrt{(12^{2}+4^{2}) }$m/s

                                            $=\sqrt{(144+16)}$m/s

                                            $=\sqrt{160}$m/s

Man's speed in the east direction$=3m/s$

The train will hit the man$=\sqrt{{(\sqrt{160} ^{2})+3^{2} } }$

                                 $=\sqrt{(160+9) }$

                                 $=\sqrt{169}$

                                 $=13m/s$

Therefore, the train will hit the man at $13m/s$.