Question

Rain water which falls on a flat rectangular surface of length 6m and breath 4m is transferred into a cylindrical vessel of internal radius 20cm .What will be the height of water in the cylindrical vessel of the rainfall is 1cm. Give your answer to the nearest integer. (Take π=3/4)

Answer 1

ANSWER:

METHOD 1

Volume1=Volume2

600*400*1=22/7*20*20*h

h=600*7/22

h=4200/22

h=190.90cm

METHOD 2

Length of rectangular surface (L) = 6 m = 600 cm

Breadth of rectangular surface (B) = 4 m = 400 cm

Height of rectangular surface (H) = 1 cm

Radius of cylindrical vessel (r) = 20 cm

Let the height of cylindrical vessel = h cm

Volume of rectangular surface = Volume of cylindrical vessel

⇒ L × B × H

⇒ 600 × 400 × 1

⇒ h = 190.90 cm

∴ Height of the cylindrical vessel is 190.90 cm.

Answer 2

Answer:

Height of water =1.9m

Step-by-step explanation:

Area of rectangle =6×4=24m²

Volume of water fallen on rectangular surface = Area×height

=24m²×0.01m

=0.24m³

This volume is transferred in cylindrical vessel of  internal radius 0.2m.

Let height of water in vessel =h

So Volume of water =πr²h

=(22/7)(0.2)²h

this Volume of water = volume of water fallen on rectangular surface

=0.24m³

So

(22/7)(0.04)h=0.24

h=21/11

=1.9m