Question

.Raj applied 20N force on a table, his friend Sam applied 20N in the
opposite direction on the same table. The net force will be ……………..

Answer 1

Given:-

• Force applied by Raj ,F1 = 20N
• Force applied by Sam ,F2 = 20N (In opposite direction)

To Find:-

• Net Force ,F

Solution:-

According to the Question

It is given that Raj applied 20N force on a table, his friend Sam applied 20N in the opposite direction on the same table.

we have to calculate the net force acting will be . So using formula . These forces acting opposite in direction to each other.

• F = F1-F2

where,

• F denote Net Force
• F1 denote Force applied by Raj
• F2 denote force applied by Sam

Substitute the value we get

$\longrightarrow$ F = 20N - 20N

$\longrightarrow$ F = 0 N

• Hence the net force will be 0 N.

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Answer 2

Answer:

0 N is the net force.

Explanation:

Given :-

Raj applied 20N force on a table, his friend Sam applied 20N in the opposite direction on the same table.

To find :-

Net force

Solution :-

Net force is nothing but the sum of the forces acting on a particular body, her it is the table which is applied by Raj and Sam.

So, we get :-

20N - 20N

0 N

∴ The net force will be 0 N.

Learn more :-

Resultant force :-

It is the sum of the forces acting on a particular body, suppose if Raj applied 20N and Sam applied 20N, then the resultant force will be 20N + 20N , that is 40 N.