.Raj applied 20N force on a table, his friend Sam applied 20N in the
opposite direction on the same table. The net force will be ……………..
Answers
Given:-
- Force applied by Raj ,F1 = 20N
- Force applied by Sam ,F2 = 20N (In opposite direction)
To Find:-
- Net Force ,F
Solution:-
According to the Question
It is given that Raj applied 20N force on a table, his friend Sam applied 20N in the opposite direction on the same table.
we have to calculate the net force acting will be . So using formula . These forces acting opposite in direction to each other.
- F = F1-F2
where,
- F denote Net Force
- F1 denote Force applied by Raj
- F2 denote force applied by Sam
Substitute the value we get
F = 20N - 20N
F = 0 N
- Hence the net force will be 0 N.
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Answer:
0 N is the net force.
Explanation:
Given :-
Raj applied 20N force on a table, his friend Sam applied 20N in the opposite direction on the same table.
To find :-
Net force
Solution :-
Net force is nothing but the sum of the forces acting on a particular body, her it is the table which is applied by Raj and Sam.
So, we get :-
20N - 20N
0 N
∴ The net force will be 0 N.
Learn more :-
Resultant force :-
It is the sum of the forces acting on a particular body, suppose if Raj applied 20N and Sam applied 20N, then the resultant force will be 20N + 20N , that is 40 N.