Question

Raj bought two mobile phones for ₹10000 .he sold one at the profit of 10% and the other at a loss of 10% .ravi got the same amount for each mobile .find the cost of each mobile phones.

Answer 1

Step-by-step explanation:

Let x be cost of 1st phone and y be of 2nd

ATQ

x+y=10,000

and also

(110/100)×x=(90/100)×y

=> 11x=9y

=>11x-9y = 0

solving both the equation

we get x= 4,500

and y=5,500

Answer 2

Answer:x=₹4500

y=₹5500

Step-by-step explanation:

Let the cost of 1st mobile phone be x.

And the cost of 2nd mobile phone be y.

A.T.Q

110% of x=90% of y

110x =90y

11x=9y

11x=9(10000-x)

11x=90000-9x

2x=90000

x=₹4500

y=₹5500