Math, asked by TamannaSaraswat, 1 month ago

Raj decided to celebrate his birthday in a small orphanage centre. He bought
chocolates to give to children and adults working there. Raj gave two chocolates to
each child and three chocolates to each adult working there . He distributed 120
chocolates in total.

i. If total number of children were x and total number of adults were y, then the
above situation can be written as Linear Equation in two variables x and y as:
(a) 2x + y = 120 (b) x + y = 120
(c) 3x + 2y = 120 (d) 2x + 3y =120
ii. If number of children is 30, then number of adults is:
(a) 30 (b) 20
(c) 40 (d) None of these
iii. If number of adults is 10, then number of children is:
(a) 45 (b) 40
(c) 30 (d) 20
iv. Which of the following is one of the solutions of equation formed in (i):
(a) x = 30, y = 20 (b) x = 20, y = 30
(c) x = 15, y = 30 (d) both (a) and (c)
v. When the equation formed in (i) is written in the standard form Ax + By + C = 0,
then values of A, B and C are:
(a) A= 2, B =1, C = 120 (b) A= 1, B= 1, C= 120
(c) A = 2, B= 3, C= 120 (d) A = 2, B= 3, C= 120

Answers

Answered by Anonymous
1

Step-by-step explanation:

  1. 91
  2. HOPE it helps you mate
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