Math, asked by sanjaysaini8110, 10 months ago

Raj goes to market to buy oranges. If he can bargain and reduce the price per orange by Rs.2, he can buy 30 oranges instead of 20 oranges with the money he has. How much money does he have 

Answers

Answered by nandanbunny
3

Answer:

Raj goes to market to buy oranges. If he can bargain and reduce the price per orange by ₹2, he can buy 30 oranges instead of 20 oranges, with the money he has.

Let the price of each orange be ₹x.

Raj can buy 20 oranges in the money, which he has with him, thus he has the amount of money as x × 20 = ₹20x.

Now, after bargaining the price of orange is reduced by 2 rupees, the price of each orange now is ₹x - 2 and he can buy 30 oranges. Accordingly

20x = 30(x - 2)

20x = 30x - 60

20x - 30x = - 60

—10x = —60

x = 60/10

x = 6

The price of each orange is ₹6

Therefore the money he has is 20x = 20 × ₹6 = ₹120

He can buy 30 oranges, if the price after bargaining becomes ₹6 - ₹2 = ₹4 per orange.

The total price of 30 oranges after bargaining is ₹4 × 30 = ₹120., which confirms that he has only ₹120.

Answer Raj has the money as ₹120 with him

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