Question

Raj has a sum of 800 in the form of
denominations of 10 and 20. If the total
number of notes is 50, find the number of
notes of each type.​

Answer 1

Answer:-

Given:

Total amount with Raj = Rs. 800

Total number of notes = 50

Let the number of Rs. 10 notes be x and number of Rs. 20 notes be y.

Hence,

→ x + y = 50 -- equation (1)

Also,

→ 10x + 20y = 800

→ 10(x + 2y) = 800

→ x + 2y = 800/10

→ x + 2y = 80 -- equation (2)

Subtract equation (1) from (2).

→ x + 2y - (x + y) = 80 - 50

→ x + 2y - x - y = 30

→ y = 30

Substitute y value in equation (1).

→ x + 30 = 50

→ x = 50 - 30

→ x = 20

Therefore,

• Number of Rs. 10 notes = x = 20

• Number of Rs. 20 notes = y = 30.

Answer 2

Answer:

✡ Given ✡

$\leadsto$ Raj has a sum of Rs 800 in the form of denominations of Rs 10 and Rs 20. If the total number of notes is Rs 50.

✡ To Find ✡

$\leadsto$ What is the number of notes of each type.

✡ Solution ✡

✏ Let the number of notes of Rs 10 be x

✏ Then, the number of notes of Rs 20 will be 50 - x

▶ According to the question,

$\implies$ 10x + 20(50 - x) = 800

$\implies$ 10x + 1000 - 20x = 800

$\implies$ 10x - 20x = 800 - 1000

$\implies$ - 10x = - 200

$\implies$ x = $\dfrac{200}{10}$

$\implies$ x = 20

$\therefore$ The number of notes of denominations of Rs 10 = 20

And, The number of notes of denominations of Rs 20 = 50 - 20 = 30

Explanation:

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