Question

raj has a trianglular open plot..
the question is in the photo provided​

Answer 1

Required Answer:-

Given P is the midpoint of AB and PQ || BC. By converse midpoint theoram, Q is the midpoint of AC$.$

And, PQ = BC / 2

THEN:

1) Area of ∆ABC = 1/2 × base × height

= 1/2 × BC × height (on base BC)

= 1/2 × 10 cm × 12 cm

= 60 cm² (B)

2) PQ = BC/2

➙ PQ = 10 cm /2

➙ PQ = 5 cm (A)

3) Since Q is the midpoint of AC. AQ = QC.

Then, AQ = AC / 2

➙ AQ = 11 cm / 2

➙ AQ = 5.5 cm (B)

4) Here too, P is the midpoint of AB. So, AP = PB.

Given, AP = 7 cm

Then, PB = 7 cm (A)

Answer 2

Required Answer:-

Given P is the midpoint of AB and PQ || BC. By converse midpoint theoram, Q is the midpoint of AC..

And, PQ = BC / 2

THEN:

1) Area of ∆ABC = 1/2 × base × height

= 1/2 × BC × height (on base BC)

= 1/2 × 10 cm × 12 cm

= 60 cm² (B)

2) PQ = BC/2

➙ PQ = 10 cm /2

➙ PQ = 5 cm (A)

3) Since Q is the midpoint of AC. AQ = QC.

Then, AQ = AC / 2

➙ AQ = 11 cm / 2

➙ AQ = 5.5 cm (B)

4) Here too, P is the midpoint of AB. So, AP = PB.

Given, AP = 7 cm

Then, PB = 7 cm (A)