Math, asked by skvb51299, 2 months ago

Raj invested a certain sum of money in a simple interest bond whose value grew to Rs. 400 at
the end of 3 years and to Rs. 500 at the end of another 5 years. What was the rate of interest in
which he invested his sum?
4.55%
5.88%
6.20%
8%​

Answers

Answered by abhiankita88
30

Step-by-step explanation:

Let principle be P and rate of interest is r.

Then, P×r×8100+P=300 ... (i)

and P×r×8100+P=400 ... (ii)

Subtracting Eq. (i) from Eq. (ii), we get

P×r×5100=100

Therefore, P×r=2000

From Eq. (i).

200×3100+P=300 =>P = Rs.240

Therefore, 24×r=2000

=> r = 5.88

Answered by Sauron
256

Answer:

The rate at which the sum was invested is 5.88%

Step-by-step explanation:

Consider the :

  • Rate as R
  • Principal as P

Formula here used is : SI = PRT/100

Amount at the end of 3 years = Rs. 400

Amount at the end of 8 years (3 + 5) = Rs. 500

Interest got on the money in the 5 years =

⇒ 500 - 400

Rs. 100

The interest received each year =

⇒ 100/5

Rs. 20

Interest received on 3 years =

⇒ 3 × 20

Rs. 60

___________________________

Principal invested =

As, Amount = Principal + SI

⇒ Principal = Amount in 3 years - Interest in 3 years

⇒ Principal = 400 - 60

Principal = Rs. 340

___________________________

Rate of interest by which the sum was invested :

We have -

  • Principal = Rs. 340
  • Rate = R
  • Time = 1 year
  • SI = Rs. 20

⇒ 20 = (340 × R × 1)/100

⇒ 200 = 34R

⇒ R = 200/34

R = 5.88 %

Therefore, the rate at which the sum was invested is 5.88%

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