Question

Raj is 6years older than diya. One half of Raj's age exceeds one third of diyas age by 4 years. Find their ages.

Answer 1

Let Diya's age be x
Let Raj's age be x+6
A/Q $\frac{1}{2}$(x+6) = $\frac{1}{3}x+4$
$\frac{x+6}{2} =$$\frac{x+12}{3}$
3x+18 = 2x+24
x=24-18
x=6
Diya's age = x = 6 years
Raj's age = x+6 = 6+6 = 12 years